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5x^2-5-7x=7x
We move all terms to the left:
5x^2-5-7x-(7x)=0
We add all the numbers together, and all the variables
5x^2-14x-5=0
a = 5; b = -14; c = -5;
Δ = b2-4ac
Δ = -142-4·5·(-5)
Δ = 296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{296}=\sqrt{4*74}=\sqrt{4}*\sqrt{74}=2\sqrt{74}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{74}}{2*5}=\frac{14-2\sqrt{74}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{74}}{2*5}=\frac{14+2\sqrt{74}}{10} $
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